A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
Do you think the hot weather we've had over the past few days will be an indication of the type of summer we're going to have, or do you think it's insignificant as a predictor?
A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
Is it the same station? You mention the station and parallel track. It is not clear if they are leaving from the same point of origin.
RE: Hey, Eric
Joey from GlenCove : 11:12 am : link : reply
In comment 13498248 Giantology said:
Quote:
A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
Assuming no time zones
8am
what if they engage the warp engines?
Oh, my Algebra teacher was right....I will use algebra....just didn't know didn't know it would be 53 years later on BBI...
100x=80x + 240
x=12 hours, so 6AM
It would have been a trick question if the second train was headed east....
a spider that can use it's front legs like antennae of an ant. Because predators and other spiders don't like the taste of ants, the spider is able to basically live its life in predatory peace.
A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
You lost every LIRR commuter at "a train leaves the station"!!!
RE: Hey, Eric
Joey from GlenCove : 11:12 am : link : reply
In comment 13498248 Giantology said:
Quote:
A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
Assuming no time zones
8am
what if they engage the warp engines?
Oh, my Algebra teacher was right....I will use algebra....just didn't know didn't know it would be 53 years later on BBI...
100x=80x + 240
x=12 hours, so 6AM
It would have been a trick question if the second train was headed east....
me fail math? unpossible.
At 6 AM, the first train would have traveled 80 * 12 = 960 miles. The second train would have traveled 100 * 9 = 900 miles. The correct answer is 9 AM.
The equation was correct, but the answer of 12 was for how many hours both trains were running at that pace. That's why you added 240 to 80x, to account for the 3 hours train 1 ran by itself.
you are correct.....it takes the second train 12 hours to catch the first one........but the second train left at 9PM, so it is 9AM....I mistakenly added the 12 hours to the time the first train left, instead of the second.....I stand corrected....
Assuming no time zones
8am
That's a farging trick question!!
Is it the same station? You mention the station and parallel track. It is not clear if they are leaving from the same point of origin.
B.
C.
D.
Good point.
Joey from GlenCove : 11:12 am : link : reply
In comment 13498248 Giantology said:
Quote:
A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
Assuming no time zones
8am
what if they engage the warp engines?
Oh, my Algebra teacher was right....I will use algebra....just didn't know didn't know it would be 53 years later on BBI...
100x=80x + 240
x=12 hours, so 6AM
It would have been a trick question if the second train was headed east....
B.
C.
D.
what's a harvestmen?
So Spider or Tick.....or Spider or Ant??????
You lost every LIRR commuter at "a train leaves the station"!!!
Joey from GlenCove : 11:12 am : link : reply
In comment 13498248 Giantology said:
Quote:
A train leaves the station at 6:00 P.M. traveling west at 80 mi/h. On a parallel track, a second train leaves the station 3 hours later traveling west a 100 mi/h. At what time will the second train catch up with the first?
Assuming no time zones
8am
what if they engage the warp engines?
Oh, my Algebra teacher was right....I will use algebra....just didn't know didn't know it would be 53 years later on BBI...
100x=80x + 240
x=12 hours, so 6AM
It would have been a trick question if the second train was headed east....
me fail math? unpossible.
At 6 AM, the first train would have traveled 80 * 12 = 960 miles. The second train would have traveled 100 * 9 = 900 miles. The correct answer is 9 AM.
The equation was correct, but the answer of 12 was for how many hours both trains were running at that pace. That's why you added 240 to 80x, to account for the 3 hours train 1 ran by itself.
E
Easter