Draft order

NYG would have to win 2 to avoid getting a top 3 pick.

[wins by non-common opps in parenthesis, lower total picks ahead]

1. CLE 0-9 (CLE 65 NYG 68)
2. SF 1-9 (NYG 41 SF 44)
3. NYG 1-8
4. IND 3-7 (IND 49 NYG 55)
Teams at 3-6: CIN, LAC, HOU, CHI, TB
Team at 3-5: DEN

NYG vs SF tiebreak (wins by non-common opponents, lower total picks ahead)
============================================================
NYG:: DAL, WAS, PHI, KC, LAC, OAK, DEN, DET, TB
5 + 4 + 8 + 6 + 3 + 4 + 3 + 5 + 3 = 41

NYG has 14 Automatic Pickups:
DAL-PHI, DAL-LAC, DAL-WAS, DAL-OAK, DAL-PHI, WAS-LAC, WAS-DEN, PHI-OAK, KC-OAK, KC-LAC, KC-DEN, LAC-OAK, OAK-DEN, DET-TB

Giving NYG total of 55. NYG has possible pickups in 36 games (including DEN-NE tonight).

SF:: ARI, LAR, SEA, CHI, CAR, JAC, HOU, IND, TEN
4 + 7 + 6 + 3 + 6 + 6 + 3 + 3 + 6 = 44

SF has 14 Automatic Pickups:
ARI-HOU ARI-JAC ARI-LAR, ARI-TEN, ARI-SEA
LAR-SEA LAR-TEN SEA-JAC JAC-HOU JAC-TEN JAC-IND
HOU-TEN HOU-IND IND-TEN

Giving SF total of 58. SF has possible pickups in 34 games, including CAR-MIA tomorrow night.

If total ends up the same, I'm not sure what happens with NYG/SF tiebreak.


CLE vs NYG tiebreak (wins by non-common opponents, lower total picks ahead):
-------------------------------------------------------
NYG: DAL x 2 WAS x 2, PHI x 2, SF, SEA, LAR, ARI, KC, OAK, DEN, TB
5 + 5 + 4 + 4 + 8 + 8 + 1 + 6 + 7 + 4 + 6 + 4 + 3 + 3 = 68
CLE: PIT x 2, CIN x 2, BAL x 2, NYJ, CHI GB MIN JAC TEN HOU IND
7 + 7 + 3 + 3 + 4 + 4 + 4 + 3 + 5 + 7 + 6 + 6 + 3 + 3 = 65

If total ends up the same, NYG/CLE tiebreak is decided by coin toss.